Read the problem looking for keywords and values:

Example 1:

At many golf clubs, a teaching professional provides a free 10-minute lesson to new customers. A golf magazine reports that golf facilities that provide these free lessons gain, on average, $2100 in green fees, lessons, or equipment expenditures. A teaching professional believes that the average gain exceeds 2,100, and collects data (shown below in the solution examples) on the gain from 15 clubs in his area. At the 0.05 level of significance, does the data support the claim?

What should you glean from reading the problem statement?

Using the StatCrunch t-distribution calculator [Excel:  =-T.INV(.05,14)], the critical value of t for a right-tail test with an alpha of 0.05 is 1.76.

Example solutions:

StatCrunch: The data is in column “gain.” 1. Select Stat>T Stats>One Sample>With Data. 2. In the One Sample T dialog box (2), click on “gain” in the Select Column(s) section, select the Perform Hypothesis test for µ radio button. Enter the null hypothesis, Ho: μ= 2100. Select > in the Ha: μ > 2100 and click Compute. 3. The results of the hypothesis test are in the box (with Options button) that opens. The t-test statistic is 1.85 and the p-value is 0.0425.

Excel PHStat:

The data is in column A. Select PHSTAT>One-Sample Tests>t-test for Mean, sigma unknown. In the dialog box that opens, enter the Null Hypothesis of 2100, the Level of Significance of 0.05, click on Sample Statistics Unknown, enter the range of the data values, check that the First cell contains a label, select an Upper-tail Test and click OK.

A new tab will be inserted with the name Hypothesis. The t-test statistic is 1.85 and the p-value is 0.0425.

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